Slide 1 · Pose the frame-design questionOpening · 8 min

A community greenhouse bed has a rectangular frame with length x+37 metres and width x+26 metres. Its required area is 1776 square metres, so learners must turn the design condition into a quadratic model.
- Define x as the variable width adjustment for the frame.
- Write the two changing dimensions with metres attached.
- Set the product of the dimensions equal to 1776.
- Predict which algebraic root could describe a buildable frame.
Worked example. Let the length be x+37 metres and width x+26 metres. Set (x+37)(x+26)=1776. Expand to x²+63x+962=1776. Answer: The area model is (x+37)(x+26)=1776..
Check question: In the quadratic model , what does the value represent?
- The required area of the greenhouse bed in square metres.
- The total perimeter of the greenhouse frame in metres.
- The volume of soil needed for the greenhouse bed in cubic metres.
- The value of the unknown variable in metres.
Show answer
The required area of the greenhouse bed in square metres. The expression multiplies the length and width of the frame. The product of these two dimensions must meet the area constraint, which is square metres.

